Makefile: remove accidental recipe prefix in conditional
Back in 728b9ac0c3 (Makefile(s): avoid recipe prefix in conditional statements, 2024-04-08), we prepared our Makefiles for a forthcoming change in upstream Make that would ban the recipe prefix within a conditional statement by replacing tabs (the prefix) with eight spaces. In b9d6f64393 (compat/zlib: allow use of zlib-ng as backend, 2025-01-28), a handful of recipe prefix characters were introduced in a conditional statement ('ifdef ZLIB_NG'), causing 'make' to fail on my system, which uses GNU Make 4.4.90. Remove the recipe prefix characters by replacing them with the same script as is mentioned in 728b9ac0c3. Signed-off-by: Taylor Blau <me@ttaylorr.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
Taylor Blau committed
Feb 13, 2025 at 15:25 UTC
f23179924bf4ee0e888cfbe911d9bd472918bcb4
1 file changed
+4
-4
Makefile
+4
-4
index 1853e6ddfa..82e51a80bd 100644
--- a/Makefile
+++ b/Makefile
@@ -1690,16 +1690,16 @@ IMAP_SEND_LDFLAGS += $(OPENSSL_LINK) $(OPENSSL_LIBSSL) $(LIB_4_CRYPTO)
ifdef ZLIB_NG
BASIC_CFLAGS += -DHAVE_ZLIB_NG
- ifdef ZLIB_NG_PATH
+ ifdef ZLIB_NG_PATH
BASIC_CFLAGS += -I$(ZLIB_NG_PATH)/include
EXTLIBS += $(call libpath_template,$(ZLIB_NG_PATH)/$(lib))
- endif
+ endif
EXTLIBS += -lz-ng
else
- ifdef ZLIB_PATH
+ ifdef ZLIB_PATH
BASIC_CFLAGS += -I$(ZLIB_PATH)/include
EXTLIBS += $(call libpath_template,$(ZLIB_PATH)/$(lib))
- endif
+ endif
EXTLIBS += -lz
endif