Windows: Make sure argv[0] has a path
Since the exec-path on Windows is derived from the program invocation path, we must ensure that argv[0] always has a path. Unfortunately, if a program is invoked from CMD, argv[0] has no path. But on the other hand, the C runtime offers a global variable, _pgmptr, that always has the full path to the program. We hook into main() with a preprocessor macro, where we replace argv[0]. Signed-off-by: Johannes Sixt <johannes.sixt@telecom.at> Signed-off-by: Junio C Hamano <gitster@pobox.com>
Johannes Sixt committed
Jul 21, 2008 at 21:19 UTC
35eeef47220c68c92d0f377f5678c42da2232c20
1 file changed
+12
compat/mingw.h
+12
@@ -223,3 +223,15 @@ void mingw_open_html(const char *path);
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char **copy_environ(void);
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void free_environ(char **env);
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char **env_setenv(char **env, const char *name);
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+
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+/*
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+ * A replacement of main() that ensures that argv[0] has a path
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+ */
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+
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+#define main(c,v) main(int argc, const char **argv) \
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+{ \
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+ static int mingw_main(); \
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+ argv[0] = xstrdup(_pgmptr); \
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+ return mingw_main(argc, argv); \
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+} \
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+static int mingw_main(c,v)