revision: clarify a 'return NULL' in get_reference()
When we know a pointer variable is NULL, it's clearer to explicitly return NULL than to return that variable. In get_reference(), when 'object' is NULL, we already return NULL when 'revs->exclude_promisor_objects && is_promisor_object(oid)' is true, but we return 'object' when 'revs->ignore_missing' is true. Let's make the code clearer and more uniform by also explicitly returning NULL when 'revs->ignore_missing' is true. Helped-by: Eric Sunshine <sunshine@sunshineco.com> Signed-off-by: Christian Couder <chriscool@tuxfamily.org> Signed-off-by: Junio C Hamano <gitster@pobox.com>
Christian Couder committed
Feb 14, 2024 at 15:25 UTC
3ff56af99b1c9becd9e603b59986359f553e62a8
1 file changed
+1
-1
revision.c
+1
-1
index 2424c9bd67..4c5cd7c3ce 100644
--- a/revision.c
+++ b/revision.c
@@ -385,7 +385,7 @@ static struct object *get_reference(struct rev_info *revs, const char *name,
if (!object) {
if (revs->ignore_missing)
- return object;
+ return NULL;
if (revs->exclude_promisor_objects && is_promisor_object(oid))
return NULL;
die("bad object %s", name);