fetch: avoid unnecessary work when there is no current branch
As pointed out by CodeQL, `branch_get()` may return `NULL`, in which case `branch_has_merge_config()` would return early, but we can even avoid enumerating the refs prefixes in that case, saving even more CPU cycles. Technically, we should enclose these two statements in an `if (branch) {...}` block, but the indentation is already quite deep, therefore I refrained from doing that. Signed-off-by: Johannes Schindelin <johannes.schindelin@gmx.de> Signed-off-by: Junio C Hamano <gitster@pobox.com>
Johannes Schindelin committed
May 15, 2025 at 13:11 UTC
6c91162449cb0a2fe3c42a1caa232444afed9c7c
1 file changed
+1
-1
builtin/fetch.c
+1
-1
index c1a1434c70..40a0e8d244 100644
--- a/builtin/fetch.c
+++ b/builtin/fetch.c
@@ -1728,7 +1728,7 @@ static int do_fetch(struct transport *transport,
if (transport->remote->follow_remote_head != FOLLOW_REMOTE_NEVER)
do_set_head = 1;
}
- if (branch_has_merge_config(branch) &&
+ if (branch && branch_has_merge_config(branch) &&
!strcmp(branch->remote_name, transport->remote->name)) {
int i;
for (i = 0; i < branch->merge_nr; i++) {