Makefile: remove unused @@PERLLIBDIR@@ substitution variable
Junio noticed that this variable is not quoted correctly when it is passed to sed. As a shell-quoted string, it should be inside single-quotes like $(perllibdir_relative_SQ), not outside them like $INSTLIBDIR. In fact, this substitution variable is not used. Simplify by removing it. Reported-by: Junio C Hamano <gitster@pobox.com> Signed-off-by: Jonathan Nieder <jrnieder@gmail.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
Jonathan Nieder committed
Apr 23, 2018 at 16:24 UTC
90df2173f24c941de01f9d104c64d940fcaa4581
1 file changed
-1
Makefile
-1
@@ -2109,7 +2109,6 @@ GIT-PERL-HEADER: $(PERL_HEADER_TEMPLATE) GIT-PERL-DEFINES Makefile
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INSTLIBDIR="$$INSTLIBDIR$${INSTLIBDIR_EXTRA:+:$$INSTLIBDIR_EXTRA}" && \
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sed -e 's=@@PATHSEP@@=$(pathsep)=g' \
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-e 's=@@INSTLIBDIR@@='$$INSTLIBDIR'=g' \
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- -e 's=@@PERLLIBDIR@@='$(perllibdir_SQ)'=g' \
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-e 's=@@PERLLIBDIR_REL@@=$(perllibdir_relative_SQ)=g' \
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-e 's=@@GITEXECDIR_REL@@=$(gitexecdir_relative_SQ)=g' \
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-e 's=@@LOCALEDIR_REL@@=$(localedir_relative_SQ)=g' \