99
} while (lo < hi);
100
return -lo-1;
101
}
102
-
103
-/*
104
- * Conventional binary search loop looks like this:
105
- *
106
- * unsigned lo, hi;
107
- * do {
108
- * unsigned mi = (lo + hi) / 2;
109
- * int cmp = "entry pointed at by mi" minus "target";
110
- * if (!cmp)
111
- * return (mi is the wanted one)
112
- * if (cmp > 0)
113
- * hi = mi; "mi is larger than target"
114
- * else
115
- * lo = mi+1; "mi is smaller than target"
116
- * } while (lo < hi);
117
- *
118
- * The invariants are:
119
- *
120
- * - When entering the loop, lo points at a slot that is never
121
- * above the target (it could be at the target), hi points at a
122
- * slot that is guaranteed to be above the target (it can never
123
- * be at the target).
124
- *
125
- * - We find a point 'mi' between lo and hi (mi could be the same
126
- * as lo, but never can be as same as hi), and check if it hits
127
- * the target. There are three cases:
128
- *
129
- * - if it is a hit, we are happy.
130
- *
131
- * - if it is strictly higher than the target, we set it to hi,
132
- * and repeat the search.
133
- *
134
- * - if it is strictly lower than the target, we update lo to
135
- * one slot after it, because we allow lo to be at the target.
136
- *
137
- * If the loop exits, there is no matching entry.
138
- *
139
- * When choosing 'mi', we do not have to take the "middle" but
140
- * anywhere in between lo and hi, as long as lo <= mi < hi is
141
- * satisfied. When we somehow know that the distance between the
142
- * target and lo is much shorter than the target and hi, we could
143
- * pick mi that is much closer to lo than the midway.
144
- *
145
- * Now, we can take advantage of the fact that SHA-1 is a good hash
146
- * function, and as long as there are enough entries in the table, we
147
- * can expect uniform distribution. An entry that begins with for
148
- * example "deadbeef..." is much likely to appear much later than in
149
- * the midway of the table. It can reasonably be expected to be near
150
- * 87% (222/256) from the top of the table.
151
- *
152
- * However, we do not want to pick "mi" too precisely. If the entry at
153
- * the 87% in the above example turns out to be higher than the target
154
- * we are looking for, we would end up narrowing the search space down
155
- * only by 13%, instead of 50% we would get if we did a simple binary
156
- * search. So we would want to hedge our bets by being less aggressive.
157
- *
158
- * The table at "table" holds at least "nr" entries of "elem_size"
159
- * bytes each. Each entry has the SHA-1 key at "key_offset". The
160
- * table is sorted by the SHA-1 key of the entries. The caller wants
161
- * to find the entry with "key", and knows that the entry at "lo" is
162
- * not higher than the entry it is looking for, and that the entry at
163
- * "hi" is higher than the entry it is looking for.
164
- */
165
-int sha1_entry_pos(const void *table,
166
- size_t elem_size,
167
- size_t key_offset,
168
- unsigned lo, unsigned hi, unsigned nr,
169
- const unsigned char *key)
170
-{
171
- const unsigned char *base = table;
172
- const unsigned char *hi_key, *lo_key;
173
- unsigned ofs_0;
174
- static int debug_lookup = -1;
175
-
176
- if (debug_lookup < 0)
177
- debug_lookup = !!getenv("GIT_DEBUG_LOOKUP");
178
-
179
- if (!nr || lo >= hi)
180
- return -1;
181
-
182
- if (nr == hi)
183
- hi_key = NULL;
184
- else
185
- hi_key = base + elem_size * hi + key_offset;
186
- lo_key = base + elem_size * lo + key_offset;
187
-
188
- ofs_0 = 0;
189
- do {
190
- int cmp;
191
- unsigned ofs, mi, range;
192
- unsigned lov, hiv, kyv;
193
- const unsigned char *mi_key;
194
-
195
- range = hi - lo;
196
- if (hi_key) {
197
- for (ofs = ofs_0; ofs < 20; ofs++)
198
- if (lo_key[ofs] != hi_key[ofs])
199
- break;
200
- ofs_0 = ofs;
201
- /*
202
- * byte 0 thru (ofs-1) are the same between
203
- * lo and hi; ofs is the first byte that is
204
- * different.
205
- *
206
- * If ofs==20, then no bytes are different,
207
- * meaning we have entries with duplicate
208
- * keys. We know that we are in a solid run
209
- * of this entry (because the entries are
210
- * sorted, and our lo and hi are the same,
211
- * there can be nothing but this single key
212
- * in between). So we can stop the search.
213
- * Either one of these entries is it (and
214
- * we do not care which), or we do not have
215
- * it.
216
- *
217
- * Furthermore, we know that one of our
218
- * endpoints must be the edge of the run of
219
- * duplicates. For example, given this
220
- * sequence:
221
- *
222
- * idx 0 1 2 3 4 5
223
- * key A C C C C D
224
- *
225
- * If we are searching for "B", we might
226
- * hit the duplicate run at lo=1, hi=3
227
- * (e.g., by first mi=3, then mi=0). But we
228
- * can never have lo > 1, because B < C.
229
- * That is, if our key is less than the
230
- * run, we know that "lo" is the edge, but
231
- * we can say nothing of "hi". Similarly,
232
- * if our key is greater than the run, we
233
- * know that "hi" is the edge, but we can
234
- * say nothing of "lo".
235
- *
236
- * Therefore if we do not find it, we also
237
- * know where it would go if it did exist:
238
- * just on the far side of the edge that we
239
- * know about.
240
- */
241
- if (ofs == 20) {
242
- mi = lo;
243
- mi_key = base + elem_size * mi + key_offset;
244
- cmp = memcmp(mi_key, key, 20);
245
- if (!cmp)
246
- return mi;
247
- if (cmp < 0)
248
- return -1 - hi;
249
- else
250
- return -1 - lo;
251
- }
252
-
253
- hiv = hi_key[ofs_0];
254
- if (ofs_0 < 19)
255
- hiv = (hiv << 8) | hi_key[ofs_0+1];
256
- } else {
257
- hiv = 256;
258
- if (ofs_0 < 19)
259
- hiv <<= 8;
260
- }
261
- lov = lo_key[ofs_0];
262
- kyv = key[ofs_0];
263
- if (ofs_0 < 19) {
264
- lov = (lov << 8) | lo_key[ofs_0+1];
265
- kyv = (kyv << 8) | key[ofs_0+1];
266
- }
267
- assert(lov < hiv);
268
-
269
- if (kyv < lov)
270
- return -1 - lo;
271
- if (hiv < kyv)
272
- return -1 - hi;
273
-
274
- /*
275
- * Even if we know the target is much closer to 'hi'
276
- * than 'lo', if we pick too precisely and overshoot
277
- * (e.g. when we know 'mi' is closer to 'hi' than to
278
- * 'lo', pick 'mi' that is higher than the target), we
279
- * end up narrowing the search space by a smaller
280
- * amount (i.e. the distance between 'mi' and 'hi')
281
- * than what we would have (i.e. about half of 'lo'
282
- * and 'hi'). Hedge our bets to pick 'mi' less
283
- * aggressively, i.e. make 'mi' a bit closer to the
284
- * middle than we would otherwise pick.
285
- */
286
- kyv = (kyv * 6 + lov + hiv) / 8;
287
- if (lov < hiv - 1) {
288
- if (kyv == lov)
289
- kyv++;
290
- else if (kyv == hiv)
291
- kyv--;
292
- }
293
- mi = (range - 1) * (kyv - lov) / (hiv - lov) + lo;
294
-
295
- if (debug_lookup) {
296
- printf("lo %u hi %u rg %u mi %u ", lo, hi, range, mi);
297
- printf("ofs %u lov %x, hiv %x, kyv %x\n",
298
- ofs_0, lov, hiv, kyv);
299
- }
300
- if (!(lo <= mi && mi < hi))
301
- die("assertion failure lo %u mi %u hi %u %s",
302
- lo, mi, hi, sha1_to_hex(key));
303
-
304
- mi_key = base + elem_size * mi + key_offset;
305
- cmp = memcmp(mi_key + ofs_0, key + ofs_0, 20 - ofs_0);
306
- if (!cmp)
307
- return mi;
308
- if (cmp > 0) {
309
- hi = mi;
310
- hi_key = mi_key;
311
- } else {
312
- lo = mi + 1;
313
- lo_key = mi_key + elem_size;
314
- }
315
- } while (lo < hi);
316
- return -lo-1;
317
-}